126x-3x^2=0

Solution for 126x-3x^2=0 equation:

126x-3x^2=0

a = -3; b = 126; c = 0;
Δ = b2-4ac
Δ = 1262-4·(-3)·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-126}{2*-3}=\frac{-252}{-6}
=+42
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+126}{2*-3}=\frac{0}{-6}
=0
$